Two particles each of equal mass (m) move along a circle of radius (r) under the action of their mutual dravitational. Find the speed of each particle.

Explanation

For the circular motion of each particle, `(mv^(2))/r=(Gm m)/((2r)^(2)) implies v^(2) = (Gm)/(4r) implies v=1/2 sqrt((Gm)/r)`.