One side of square `ABCD` is on the line `y=2x-17` and other two vertices are on parabola `y=x^(2)`, if the minimum area of square is `A` then find `A/16`.

Consider one sides AB of a square ABCD in order on line y=2x-17 , and other two vertices C, D on y=x^(2) The maximum possible area of square ABCD is

Consider one sides AB of a square ABCD in order on line y=2x-17 , and other two vertices C, D on y=x^(2) The maximum possible area of square ABCD is

Consider one sides AB of a square ABCD in order on line y=2x-17 , and other two vertices C, D on y=x^(2) The maximum possible area of square ABCD is

Consider one sides AB of a square ABCD in order on line y=2x-17 , and other two vertices C, D on y=x^(2) The minimum intercept of line CD on the y-axis is

Consider one sides AB of a square ABCD in order on line y=2x-17 , and other two vertices C, D on y=x^(2) The minimum intercept of line CD on the y-axis is

Consider one sides AB of a square ABCD in order on line y=2x-17 , and other two vertices C, D on y=x^(2) The minimum intercept of line CD on the y-axis is

Let ABCD be a square such that the side AB is on the line 2x-y=17 and two vertices C and D are on the parabola y=x^(2) . If length of side of ABCD is less than 10 and its area is A, then A is equal to

Two sides of a square lie on the lines x+y-1=0 and x+y+2 then its area is:

Two sides of a square lie on the lines x+y=1 and x+y+2=0. What is its area?

Two sides of a square lie on the lines x+y=1a n dx+y+2=0. What is its area?