Home
Class 12
PHYSICS
If radius of a spherical bubble starts t...

If radius of a spherical bubble starts to increase with time t as `r=0.5t`. What is the rate of change of volume of the bubble with time `t=4s`?

A

`8pi` units/s

B

`4pi` units/s

C

`2pi` units/s

D

`pi` units/s

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN|Exercise Basic Maths (Integration)|12 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Graphs))|30 Videos
  • RACE

    ALLEN|Exercise Basic Maths (Trigonometry)|22 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN|Exercise EXERCISE-III|28 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

The radius of an air bubble in increasing at the rate of 0.5cm/s. Find the rate of change of its volume, when the radius is 1.5 cm.

The radius of spherical bubble is changing with time. The rate of change of its volume is given by :

The radius of a soap - bubble is increasing at the rate of 0.7cm//s . Find the rate of increase of : its volume when the radius is 5 cm.

The surface area of a spherical bubble is increasing at the rate of 2cm^(2)/s. When the radius of the bubble is 6cm at what rate is the volume of the bubble increasing?

The radius of an air bubble is increasing at the rate of 0.5 cm/sec. At what rate is the volume of the bubble increasing when the radius is 1 cm?

The radius of a circular soap bubble is increasing at the rate of 0.2cm/s. Find the rate of change of its: (I) Volume (II) Surface area when the radius is 4 cm.

The radius of a spherical soap bubble is increasing at the rate of 0.2 cm/sec. Find the rate of increase of its surface area, when the radius is 7 cm.

The radius of an air bubble is increasing at the rate of (1)/(2)cm/s At what rate is the volume of the bubble increasing when the radius is 1cm?

Radius of a spherical balloon is increasing with respect to time at the rate of 2//pi" "m//s . Find the rate of change in volume (in m^(3)//s ) of the balloon when radius is 0.5 m?

The radius of a spherical soap bubble is increasing at the rate of 0.2cm/sec. Find the rate of increese of its surface area,when the radius is 7cm.

ALLEN-RACE-Basic Maths (Differentiation)
  1. If the velocity of a paraticle moving along x-axis is given as v=(4t^(...

    Text Solution

    |

  2. The displacement x of particle moving in one dimension, under the acti...

    Text Solution

    |

  3. A car moves along a straight line whose equation of motion is given by...

    Text Solution

    |

  4. A particle moves along X-axis in such a way that its coordinate X vari...

    Text Solution

    |

  5. Relation between displacement x and time t is x=2-5t+6t^(2), the initi...

    Text Solution

    |

  6. The displacement 'x' of a particle moving along a straight line at tim...

    Text Solution

    |

  7. If the distance covered by a particle is given by the relation x=at^(2...

    Text Solution

    |

  8. The displacement of a particle is given by x=a(0)+(a(1)t)/(3)-(a(2)t...

    Text Solution

    |

  9. If y=(x^(2))/((x+1))"then"(dy)/(dx)"is":-

    Text Solution

    |

  10. If v=(t+2)(t+3) then acceleration(i.e(dv)/(dt)) at t=1 sec.

    Text Solution

    |

  11. If y=log(e)x+sinx+e^(x)" then "(dy)/(dx) is

    Text Solution

    |

  12. (d)/(dx)(e^(100))=…………………

    Text Solution

    |

  13. (d)/(dx)(sin120^(@))=…………

    Text Solution

    |

  14. If y=x^(3)cosx" then "(dy)/(dx)=……………………

    Text Solution

    |

  15. If v=(t^(2)-4t+10^(5))m/s where t is in second. Find acceleration at t...

    Text Solution

    |

  16. If y=sinx+cosx" then "(d^(2)y)/(dx^(2)) is :-

    Text Solution

    |

  17. If vpropt^(5//2) then

    Text Solution

    |

  18. If radius of a spherical bubble starts to increase with time t as r=0....

    Text Solution

    |

  19. The radius of spherical bubble is changing with time. The rate of chan...

    Text Solution

    |

  20. Given that y=(10)/(sinx+sqrt(3)cosx).Minimum value of y is

    Text Solution

    |