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A person moves towards north with unifor...

A person moves towards north with uniform speed of 15 m/s and cover 16 m. After this he moves towards east and covers 6 m and finallt covers 8 m distance with same speed in south. Find out
(i) Distance travelled by person
(ii) Displacement of person
(iii) Average velocity of person

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The correct Answer is:
To solve the problem step by step, let's break it down into the required parts: ### Step 1: Calculate the Total Distance Travelled The total distance travelled by the person is the sum of all the distances covered in each direction. - Distance travelled north = 16 m - Distance travelled east = 6 m - Distance travelled south = 8 m **Total Distance = Distance North + Distance East + Distance South** \[ \text{Total Distance} = 16 \, \text{m} + 6 \, \text{m} + 8 \, \text{m} = 30 \, \text{m} \] ### Step 2: Calculate the Displacement Displacement is the shortest distance from the initial position to the final position. We can visualize the movements as a right triangle: 1. The person moves north (16 m). 2. Then east (6 m). 3. Finally south (8 m). To find the final position, we can calculate the net north-south movement: - Net north-south movement = Distance North - Distance South \[ \text{Net North-South} = 16 \, \text{m} - 8 \, \text{m} = 8 \, \text{m} \text{ (North)} \] Now, we have: - North-South component = 8 m (North) - East-West component = 6 m (East) Using the Pythagorean theorem to find the displacement: \[ \text{Displacement} = \sqrt{(\text{North-South})^2 + (\text{East-West})^2} \] \[ \text{Displacement} = \sqrt{(8 \, \text{m})^2 + (6 \, \text{m})^2} = \sqrt{64 + 36} = \sqrt{100} = 10 \, \text{m} \] ### Step 3: Calculate the Average Velocity Average velocity is defined as the total displacement divided by the total time taken. **Total Time Calculation:** 1. Time taken to travel north: \[ \text{Time North} = \frac{\text{Distance}}{\text{Speed}} = \frac{16 \, \text{m}}{15 \, \text{m/s}} = \frac{16}{15} \, \text{s} \] 2. Time taken to travel east: \[ \text{Time East} = \frac{6 \, \text{m}}{15 \, \text{m/s}} = \frac{6}{15} \, \text{s} = \frac{2}{5} \, \text{s} \] 3. Time taken to travel south: \[ \text{Time South} = \frac{8 \, \text{m}}{15 \, \text{m/s}} = \frac{8}{15} \, \text{s} \] **Total Time = Time North + Time East + Time South** \[ \text{Total Time} = \frac{16}{15} + \frac{2}{5} + \frac{8}{15} \] To add these, convert \(\frac{2}{5}\) to a fraction with a denominator of 15: \[ \frac{2}{5} = \frac{6}{15} \] Now, add: \[ \text{Total Time} = \frac{16}{15} + \frac{6}{15} + \frac{8}{15} = \frac{30}{15} = 2 \, \text{s} \] **Average Velocity Calculation:** \[ \text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}} = \frac{10 \, \text{m}}{2 \, \text{s}} = 5 \, \text{m/s} \] ### Final Answers: (i) Total Distance travelled = 30 m (ii) Displacement = 10 m (iii) Average Velocity = 5 m/s ---
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