A body is projected at an angle of `45^(@)` with horizontal with velocity of `40sqrt(2)m//s`. Find out
(i) Maximum height attained by body
(ii) Time of flight
(iii) Horizontal range
(iv) Velocity at maximum height
(v) The ratio of Kinetic energy to potential energy at highest point
(vi) The part equation of projectile, assuming point of projection as origin and consider x and y are horizontal and vertical distance in meter
(vii) The horizontal distance covered by body in 2 second
(viii) The vertical distance covered by body in 2 second

Answer

(i) 80 m
(ii) 8 sec (iii) 320 m
(iv) 40 m/s
(v) 1 : 1
(vi)`y=x-(x^(2))/(320)m`
(vii) 80 m
(viii) 60 m