A man of mass 60 kg is in a lift and lift is accelerating upwards with acceleration `4 m//s^(2)`. Calculate effective weight of man in lift.

Answer

To calculate the effective weight of a man in a lift that is accelerating upwards, we can follow these steps:

### Step 1: Identify the given values
- Mass of the man (m) = 60 kg
- Acceleration of the lift (a) = 4 m/s²
- Acceleration due to gravity (g) = 10 m/s² (approximately)

### Step 2: Calculate the effective weight
The effective weight of the man when the lift is accelerating upwards can be calculated using the formula:
\[ \text{Effective Weight} = m \cdot (g + a) \]

### Step 3: Substitute the values into the formula
Substituting the known values:
\[ \text{Effective Weight} = 60 \, \text{kg} \cdot (10 \, \text{m/s}^2 + 4 \, \text{m/s}^2) \]

### Step 4: Perform the addition inside the parentheses
\[ g + a = 10 \, \text{m/s}^2 + 4 \, \text{m/s}^2 = 14 \, \text{m/s}^2 \]

### Step 5: Calculate the effective weight
Now, substitute this result back into the equation:
\[ \text{Effective Weight} = 60 \, \text{kg} \cdot 14 \, \text{m/s}^2 \]
\[ \text{Effective Weight} = 840 \, \text{N} \]

### Final Answer
The effective weight of the man in the lift is **840 Newtons**.

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