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A solid cylinder of mass M and radius R rolls down an inclined plane of height h. The angular velocity of the cylinder when it reaches the bottom of the plane will be :

A

`(1)/(2R)sqrt(gh)`

B

`(2)/(R)sqrt(gh)`

C

`(2)/(R)sqrt((gh)/(3))`

D

`(2)/(R)sqrt((gh)/(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
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