At what temperature, DeltaG of a reactio...

At what temperature, `DeltaG` of a reaction is equal to `-5.2 kJ mol^(-1)` ? `DeltaH` and `DeltaS` of the reaction are respectively `145.6 kJ mol^(-1)` and `116 JK^(-1)`.

Similar Questions

Explore conceptually related problems

The temperature in K at which DeltaG=0 for a given reaction with DeltaH=-20.5 kJ mol^(-1) and DeltaS=-50.0 JK^(-1) mol^(-1) is

Calculate the temperature at which DeltaG=-5.2 kJ mol^-1 ,DeltaH=145.6kJ mol^-1 and DeltaS=216 JK^-1 mol^-1 for a chemical reaction

The temperature of K at which Delta G =0 for a given reaction with Delta H= -20.5 kJ mol^(-1) and Delta S =- 50.0 JK^(-1)mol^(-1)

Calculate the temperature at which DeltaG = -5.2 kJ mol^-1, DeltaH = 145.6 kJ mol^-1 and DeltaS = 216 J K^-1 mol^-1 for a chemical reaction

For a particular reaction, triangleH^@ = -38.3 kJ mol^-1 and triangleS^@ = -113JK^-1 mol^-1 . This reaction is

At 1 atm pressure, DeltaS=75JK^(-1)mol^(-1),DeltaH=30kJ" "mol^(-1) , the temperature of the reaction at equilibrium is