Given `12sintheta +5costheta=2x^2-8x+21 and theta` and x are the solutions of the above then `thetax` is

If sintheta+costheta=x then sintheta-costheta=?

Eliminate theta x=a sintheta , y=a costheta

The vertices of a DeltaABC has coordinates (costheta,sintheta),(sintheta,-costheta) and (1,2). As theta varies the locus of centroid of the triangle is the circle

Vertices of a variable triangle are (3,4); (5costheta, 5sintheta) and (5sintheta,-5costheta) where theta is a parameter then the locus of its orthocentre is a. (x+y-1)^2+(x-y-7)^2=100 b. (x+y-7)^2+(x-y-1)^2=100 c. (x+y-7)^2+(x+y-1)^2=100 d. (x+y-7)^2+(x-y+1)^2=100

Let P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = 12 sintheta} be two sets. Then:

Let P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = 12 sintheta} be two sets. Then:

If the centroid of traingle formed by point (0,0) (costheta,sintheta) " and "(sintheta,-costheta) lies on the line y=2x, then the value of tan theta is

If 5 sin theta - 4 cos theta = 0, 0^(@) lt theta lt 90^(@) , then the value of (5sintheta-2costheta)/(sintheta+3costheta) is :