If the vector equation of a plane is`vecr.(1+s-t)veci+(2-s)vecj+(3-2+2t)veck`, find its equation in Cartesian form.

Find the unit vector in the direction of the vector veci-2vecj+3veck .

Find the vector equation of the line joining the points 2veci+4j+3veck and -4veci+3vecj-veck .

Find the cartesian from of the equation of the plane vecr=(s-2t) hat i+(3-t) hatj+(2s+t)hat k

Find the Cartesian from the equation of the plane vecr=(s-2t)hati+(3-t)hatj+(2s+t)hatk .

The cartesian form of the equation of plane barr=(s+t)hati+(2+t)hatj+(3s+2t)hatk is

For given vectors, veca = 2veci - vecj + 2veck, vecb = -veci + vecj - veck find the unit vector in the direction of the vector veca+vecb

The shortest distance between the line vecr = (1-t) veci + (t-2) vecj + (3-2t) veck and vecr = (s + 1) vect + (2s -1) vecj - (2s + 1) veck is

Find the vector equation of the through the points 2veci+vecj-3veck and parallel to vector veci+2vecj+veck

Find the point of intersection of the line vecr=(vecj-veck)+s(2veci-vecj+veck) and Xz-plane

Find the vector equation of the line through the points 2veci+vecj-3veck and parallel to vector veci+2vecj+veck