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An observer 1.6 m tall is 20sqrt(3) m...

An observer 1.6 m tall is `20sqrt(3)` m away from a tower. The angle of elevation from his eye to the top of the tower is `30o` . The height of the tower is: (a) 21.6 m (b) 23.2 m (c) 24.72 m (d) None of these

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An observer , 1.7 m tall , is 20sqrt(3) m away from a tower . The angle of elevation from the eye of observer to the top of tower is 30^(@) . Find the height of tower .

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Knowledge Check

  • At a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30^@ The height of the tower is

    A
    `20 sqrt(3) m`
    B
    `(20)/(sqrt(3))m`
    C
    `(sqrt(3))/(20m )`
    D
    None of these
  • From a point 20 m away from the foot of a tower, the angle of elevation of the top of the tower is 30^(@) . The height of the tower is

    A
    ` 10 sqrt(3) m`
    B
    `20 sqrt(3)` m
    C
    `10/sqrt(3)` m
    D
    `(20)/(sqrt(3))m`
  • At a point 20 m away from the foot of a tower the angle of elevation of the top of the tower is 30^(@) The height of the tower is

    A
    `20sqrt3m`
    B
    `(20)/(sqrt3)m`
    C
    `(sqrt3)/(20)m`
    D
    None of these
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    An observer,1.5m tall,is 28.5m away from a tower 30m high.Determine the angle of elevation of the top of the tower from his eye.

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    An observer 1.5 m tall is 28.5 m away from a tower and the angle of elevation of the top of the tower from the eye of the observer is 45^(@) . The height of the tower is

    A 1.6 m tall observer is 45 metres away from a tower .The angle of elevation from his eye to the top of the tower is 30^(@) , then the height of the tower in metres is (Take sqrt(3)=1.732)

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