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Br(2)+OH rarr BrO(3)^(-1)+Br+H(2)O...

Br_(2)+OH rarr BrO_(3)^(-1)+Br+H_(2)O

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Balance the half equation Br_(2) rarr BrO_(3)^(-) + Br^(-) by ion-electron method.

In the disproportionation reaction ( unbalanced ) , Br_(2) + OH^(-) rarr Br^(-) + BrO_(3)^(-) + H_(2)O The ratio of Br_(2) molecules undergoing oxidation and reduction is "P/Q" then "P+Q" is

Consider the following reactions. Br_(2)+OH^(-)rarrBrO_(3)^(-)+Br^(-)+H_(2)O (unbalanced). select the correct statement

Balance the redox reaction by half reaction method : Br_(2)+ H_(2)O_(2) to BrO_(3)^(-) + H_(2)O (in acidic medium)

Balance the redox reaction by half reaction method : Br_(2)+ H_(2)O_(2) to BrO_(3)^(-) + H_(2)O (in acidic medium)

What is the coefficient for OH^(-) after the equation __ Br_(2)+ __ OH^(-)rarr __ Br^(-)+ __ BrO_(3)^(-)+ __ H_(2)O is balanced with the smallest interger coefficients ?

The oxidant and the reductant species resectively of the reactants in the reaction Br_2 + OH^- rarr Br^(-) + BrO_3^(-)+ H_2O

In hot alkaline solution, disproportionates to Br^(-) and BrO_(3)^(-) . 3Br_(2) + 6OH^(-) to 5Br(-) + BrO_(3)^(-) + 3H_(2)O Hence, equivalent weight of Br2 is (molecular weight = M)