If velocity of a particle is given by `v=3t^(2)-6t +4`. Find its displacement from `t=0` to `3 secs`.

Velocity of a particle is given by v = (3t ^(2) +2t) m/s. Find its average velocity between t = 0 to t=3s and also find its acceleration at t = 3s. Motion of the particle is in one dimension.

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its displacement when acceleration is 14" ft/sec"^(2) , is

The velocity of a particle is given by v=(5t^(2)-6t+5)m//s where t is time in seconds. Find its acceleration at t=4 second.

The displacement of a particle at time t is given by s= 2t^(3) -5t^(2)+ 4t-3 . Find the velocity when t = 2 sec.

The displacement s of a particle at a time t is given bys =t^(3)-4t^(2)-5t. Find its velocity and acceleration at t=2 .

The displacement of a particle is given by y (t) =2t ^(2) +5m. Hence its velocity at the end of 6 sec. will be ...... m/s.

A particle moves in a straight line and its velocity v at time t seconds is given by v=(6t^(2)-2t+3) cm/sec. Find the distance travelled by the particle during the first 5 second after the start.

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)

The angular displacement of a particle is given by theta=t^(3)+ t^(2)+ t+1 then, its angular velocity at t = 2sec is ……….. rad s^(-1)