In the given figure `DE||BC and AD:DB =5:4`
Find the ratio `ar (Delta DEF) : ar (Delta CFB)`

In the given figure, DE//BC and AD:DB=5:4, then (DeltaDEF)/(DeltaCFB) =

In Figure 1,PQ|BC and AP:PB=1:2* find the ratio of (ar Delta APQ)/(ar Delta ABC)

In the given figure, DE||BC and DE:BC=3:5 . Calculate the ratio of areas of Delta ADE and the trpezium BCED.

In the given figure, DE//BC and AD : DB = 5 : 4, then (triangle DEF)/(triangle CFB) =

In the given figure, DE is parallel to the base BC of triangle ABC and AD: DB = 5: 4. Find the ratio : ("Area of "DeltaDEF)/("Area of"Delta BFC)

In the given figure, DE||BC . If DE : BC = 3 : 5 , find (ar(ADE))/(ar(BCED)) .

In figure, if DE abs() BC, then find the ratio of ar ( DeltaADE ) and ar(DECB).

In figure, if DE abs() BC, then find the ratio of ar ( DeltaADE ) and ar(DECB).

In the given figure DE || BC . If AD = 1.5 cm , BD = 2AD , then find (ar(Delta "ADE"))/(ar("trapezium BCED"))