(2,4),(2,6),(2+sqrt(3),5)" form an equilateral triangle."

Show that the points (2,4),(2,6) (2+sqrt3,5) form an equilateral triangle.

Show that the points (2,4),(2,6) (2+sqrt3,5) form an equilateral triangle.

The co-ordinates of the third vertex C on the x-axis so that A(2,0) , B(2+2sqrt3,6) and C form an equilateral triangle is :

If three points (0,0),(3,sqrt(3)) and (3,lambda) form an equilateral triangle,then lambda=(a)2 (b) -3(c)-4(d) None of these

I : The points (-2,3,5 ), (1,,2,3 ),(7,0,-1 ) are collinear. II: The points (2 ,-1,1 ) (1-3-5 ), (3,-4,-4 ) form an equilateral triangle.

Show that points (2-sqrt3 , sqrt3 +1) , (1,0) and (3,2) form an equilateral triangle .

The vertices of a triangle are (2,4),B(2,6),C(2+sqrt(3),5). The triangle is

Show that the triangle with vetices (1,2,5) (2,5,3) and (-1,3,2) is an equilateral triangle.

If three points (0,\ 0),\ (3,\ sqrt(3)) and (3,\ lambda) form an equilateral triangle, then lambda= (a) 2 (b) -3 (c) -4 (d) None of these