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If the tangent at any point (4m^2,8m^2) ...

If the tangent at any point `(4m^2,8m^2)` of `x^3-y^2=0` is a normal to the curve `x^3-y^2=0` , then find the value of `mdot`

A

`+- sqrt((2)/(9))`

B

`+- (1)/(3)`

C

`+- sqrt((9)/(2))`

D

`+- (2)/(3)`

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The correct Answer is:
A
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