At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen `(N_(2))` at 4 bar. The molar mass of gaseous molecule is:

Options

A. `28gmol^(-1)`
B. `56gml1^(-1)`
C. `112gmol^(-1)`
D. `224gmol^(-1)`

Answer

C

Explanation

Density (p)=`(Pm)/(RT)` (1 bar=0.987 atm)
`p_(N_(2))=(4xx0.987atmxx28g//mol)/(Rxx300K)`
Let the molar mass of gas be x
`p_(gas)=(2xx0.987atmxx x)/(Rxx300K)`
Given `p_("gas")=P_(N_(2))xx2`
`(2xx0.987atmxx x)/(Rxx300K)=(4xx0.987atmxx28g//mol)/(Rxx300)xx2`
`thereforex=112g//mol`