Initially, the root mean square ( rms) velocity of `N_(2)` molecules at certain temperature is u. If this temperature is doubled and all the nitrogen molecules dissociate into nitrogen atoms, then the rms velocity will be:

Options

A. 2u
B. 14u
C. 4u
D. u/2

Answer

A

Explanation

`rms(N_(2))=sqrt((3RT)/28)`
After dissociation, u. = `sqrt((3Rxx2T)/14)`
`u/(u.)=sqrt(1/4),u/(u.)=1/2,u.=2u`