500 mL of nitrogen at `27^(@)C` is cooled to `-5^(@)C` at the same pressure. The new volume becomes

Options

A. 326.32 mL
B. 446.66 mL
C. 546.66 mL
D. 771.56 mL

Answer

B

Explanation

Given initial volume `(V_(1))=500` mL, Initial temperature `(T_(1))=27^(@)C=300K` and final temperature `(T_(2))=5^(@)C` =268K
From Charle.s law :
`(V_(1))/(T_(1))=(V_(2))/(T_(2))` or `500/300=V_(2)/268`
Where `V_(2)` = New volume of gas
`V_(2)=500/300xx268=444.66mL`