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A certain gas takes three times as long ...

A certain gas takes three times as long to effuse out as helium. Its molar mass will be

A

27u

B

36u

C

64u

D

9u

Text Solution

Verified by Experts

The correct Answer is:
B
`rpropsqrt(1/M),(r_(1))/(r_(2))=sqrt((M_(2))/(M_(1)),(3r_(1))/(r_(1))=sqrt((M_(2))/4),9=(M_(2))/4`
`M_(2)=36 g`/mole
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