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The molecular velocities of two gases at...

The molecular velocities of two gases at same temperature are `u_(1)` and `u_(2)`, their masses are `m_(1)` and `m_(2)` respectively, which of the following expression is correct ?

A

`(m_(1))/(u_(1)^(2))=(m_(2))/(u_(2)^(2))`

B

`m_(1)u_(1)=m_(2)u_(2)`

C

`(m_(1))/(u_(1))=(m_(2))/(u_(2))`

D

`m_(1)u_(1)^(2)=m_(2)u_(2)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

`mu_(1)propsqrt(1/(m_(1)))` and `u_(2)propsqrt(1/(m_(2)))`
`therefore(u_(1)^(2))/(u_(2)^(2))=(m_(2))/(m_(1))thereforem_(1)i_(1)^(2)=m_(2)u_(1)^(2)=m_(2)u_(2)^(2)`
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