The ratio of Boyle's temperature and critical temperature for a gas is:

Options

A. `8/27`
B. `27/8`
C. `1/2`
D. `2/1`

Answer

B

Explanation

Boyle.s temperature,
`T_(b)=a/(Rb)` and critical temperature,
`T_(c)=(8a)/(27Rb)therefore(T_(b))/(T_(c))=27/8`