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The combustion of benzene (l) gives CO(2...

The combustion of benzene (l) gives `CO_(2)(g)` and `H_(2)O(l)`. Given that heat of combustion of benzene at constant volume is `–3263.9 kJ mol^(–1)` at `25^(@)C`, heat of combustion (in kJ` mol^(–1)`) of benzene at constant pressure will be
(R = 8.314 JK–1 mol–1)

A

4152.6

B

`-452.46`

C

3260

D

`-3267.6`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(6)H_(6)(1)+15/2O_(2)(g)to6CO_(2)(g)+3H_(2)O(l)`
`Deltan_(g)=6-15/2=-3/2`
`DeltaH=DeltaU+Deltan_(g)RT`
`=-3263.9+(-3/2)xx8.314xx298xx10^(-3)`
`=-3263.9+(-3.71)=-3267.6kJ"mol"(-1)`
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