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For a reversible adiabatic ideal gas exp...

For a reversible adiabatic ideal gas expansion `(dp)/(p)` is equal to

A

`gamma(dV)/V`

B

`-gamma(dV)/V`

C

`((gamma)/(gamma-1))(dV)/V`

D

`(dV)/V`

Text Solution

Verified by Experts

The correct Answer is:
B
For reversible adiabatic expansion `PV^(gamma)=` constant
`P_(gamma)V^(gamma-1)dV+V^(gamma)d_(P)` on differentiating we get
`:.(dP)/P=(-gamma.(dV))/V`
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