The reaction `A to B` , `DeltaH=+24 kJ//"mole"`. For the reaction `B to C`, `DeltaH=-18 kJ//"mole"`. The decreasing order of enthalpy of `A`, `B`, `C` follow the order

Options

A. A,B,C
B. B,C,A
C. C,B,A
D. C,A,B

Answer

B

Explanation

`AtoB, DeltaH=+24` kJ/mol
`impliesH_(B)-H_(A)=+24`
`BtoC,DeltaH=-18`kJ/mol
`impliesH_(C)-H_(B)=-18`……….ii
From eqs I and ii we have
`H_(C)-H_(A)=6`
`:.H_(8)gtH_(C)gtH_(A)`