Following reaction occurring in an automobile `2C_(8)H_(18)(g)+25O_(2)(g) to 16CO_(2)(g)+18H_(2)O(g)`. The sign of `triangleH, triangleS and triangleG` would be-

Options

A. `+,-,+`
B. `-,+,-`
C. `-,+,+`
D. `+,+,-`

Answer

B

Explanation

This is combustion reaction, which is always exothermic hence `DeltaH=-ve`
As the no of gaseous molecule are increasing hence entropy increases
Now `DeltaG=DeltaH-TDeltaS`
For a spontaneous reaction
`DeltaG=-ve`
Which is possible in this case as `DeltaH=-ve` and `DeltaS=+ve`.