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If the end energies of H-H, Br-Br and H-...

If the end energies of H-H, Br-Br and H-Br are 433, 192 and 364 kJ `mol^(-1)` respectively, then `DeltaH^(@)` for the reaction, `H_(2)(g)+Br_(2)(g)to2HB r(g)` is

A

`-261kJ`

B

`+103kJ`

C

`+261kJ`

D

`-103kJ`

Text Solution

Verified by Experts

The correct Answer is:
D
`H_(2)(g)+Br_(2)(g)to2HBr(g)`
`DeltaH^(@)=(BE)_("reactant")=-(BE)_("product")`
`=(433+192)-(2xx364)`
`=625-728=-103kJ`
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