When 0.2 mole of anhydrous `CuSO_(4)` is dissolved in water, the heat evolved is 1.451 kcal. If 0.2moleof `CuSO_(4).5H_(2)O` is dissolved in water, the heat absorbed is 0.264 kcal. Calculate the molar heat of hydration of `CuSO_(4)`

Options

A. 11.87 kcal
B. `-11.87` kcal
C. 17.15 kcal
D. `-17.15` kcal

Answer

D

Explanation

(i) `CuSO_(4)(s)+"aqua"toCuSO_(4)(aq)`
`Delta=(-1.451)/0.1=-14.51k "cal mol"^(-1)`
(ii)`CuSO_(4).5H_(2)O(s)+"aqua"toCuSO_(4)(aq)`
`Deltah=0.264/0.1=2.64 k "cal mol"^(-1)`
From i-ii
`CuSo_(4)(s)+5H_(2)O(l)toCuSO_(4).5H_(2)O(s),`
`DeltaH=-17.15k "cal mol"^(-1)`