Home
Class 12
CHEMISTRY
Calculate the resonance enegry of N(2)O ...

Calculate the resonance enegry of `N_(2)O` form the following data
`Delta_(f)H^(Theta) of N_(2)O = 82 kJ mol^(-1)`
Bond enegry of `N-=N, N=N, O=O,` and `N=O` bond is `946, 418, 498`, and `607 kJ mol^(-1)`, respectively.

A

`-88kJ`

B

`-66kJ`

C

`-62kJ`

D

`-44kJ`

Text Solution

Verified by Experts

The correct Answer is:
A

`N_(2)(g)+1/2O_(2)toN_(2)O(g)`
`DeltaH_(f)^(@)=(DeltaH_(N-=N)+1/2DeltaH_(O=O))-(DeltaH_(N=N)+DeltaH_(N=O))`
`=(946+1/2xx498)-(418+607)=170kJ"mol"^(-1)`
Resonance energy `=170-82=88kJ "mol"^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THE SOLID STATE

    DISHA PUBLICATION|Exercise EXERCISE -2 : CONCEPT APPLICATOR|30 Videos

Similar Questions

Explore conceptually related problems

Calcualate the resonance energy of N_(2)O from the following data : Delta_(f)H^(@) of N_(2)O= 82kJ mol^(-1) , Bond energies of N -= N , N = N , O=O and N=O bonds are 946, 418, 498 and 607 kJ mol^(-1) respectively.

Calculate the resonance energy of N_(2)O from the following data : DeltaH_(f)^(@) of N_(2)O = 82 kJ mol^(-1) , Bond energies of N equivN , N = N , O =O and N =O bonds are 946, 418, 498 and 607 kJ mol^(-1) respectively.

Knowledge Check

  • Calculate the resonance energy of N_2O from the following data, Delta_fH ofN_2O is 82KJ mol^(-1)N-=N,946 KJ mol^(-1),N=N,418KJ mol^(-1), 0 = 0 , 498 KJ mol^(-1), N = 0,607KJ mol^(-1)

    A
    `+8.85 " KJ mol"^(-1)`
    B
    `-88 " KJ mol"^(-1)`
    C
    `-8.8 " KJ mol"^(-1)`
    D
    `+88 " KJ mol"^(-1)`
  • calculateth resonance energy of N_(2)O Delta_(f)H^(-) of N_(2)O = 82 kJ mol ^(-1) bond energy of N=O = 607 kJmol ^(-1) bond energy of O=O = 498 kJ mol ^(-1) nond energy of N = N = 418 kJ mol^(-1) bond energy of N= N = 946 kJ mol ^(-1)

    A
    `82 kJ mol ^(-1)`
    B
    `-88 kJ mol ^(-1)`
    C
    `- 82 kJ mol ^(-1)`
    D
    `+ 88 kJ mol ^(-1)`
  • Use the given data to calculate the resonance energy of N_(2)O.(Delta_(f)H^(ө) of N_(2)O=82kJmol^(-1)) Bond energy of N=O to607kJmol^(-1) Bond energy of O=O to498kJmol^(-1) bond energy of N=N to418kJmol^(-1) Bond energy of N-=Nto946kJmol^(-1) Choose the correct option.

    A
    82 kJ `mol^(-1)`
    B
    `-88kJ` `mol^(-1)`
    C
    `-82` kJ `mol^(-1)`
    D
    `+88kJmol^(-1)`
  • Similar Questions

    Explore conceptually related problems

    Calculate the resonance energy of N_(2)O from the following data : DeltaH_(f)^(0) "of" N_(2)O=82 kJ "mole"^(-1) Bond energies of N-=N, N=N,O=O and N=O bonds are 946, 418, 498 and 607 kJ "mole"^(-1) respectively.

    Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mol"^(-1)

    Calculate the resonance energy of N_(2)O from the following data: DeltaH_(1)^(@) of N_(2)O = 82 kJ "mole"^(-1) . Bond energies N=N = 946 kJ "mole"^(-1) N=N = 418 kJ "mole"^(-1) O=O = 498 kJ "mole"^(-1) N=O = 607 kJ "mole"^(-1)

    Calculate the resonance enegry of NO_(2) ( :O-N=O: ) The measured enthalpy formation of NO_(2)(Delta_(f)H^(Theta)) is 34 kJ mol^(-1) . The bond energies given are: N -O rArr 222 kJ mol^(-1) N -= N rArr 946 kJ mol^(-1) O = O rArr 498 kJ mol^(-1) N = O rArr 607 kJ mol^(-1)

    H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g) DeltaH =- 242 kJ mol^(-1) Bond energy of H_(2) and O_(2) is 436 and 500 kJ mol^(-1) , respectively. What is bond energy of O-H bond?