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18g glucose (C(6)H(12)O(6)) is added to ...

`18g` glucose `(C_(6)H_(12)O_(6))` is added to `178.2g` water. The vapour pressure of water (in torr) for this aqueous solution is:

A

752.4

B

759

C

7.6

D

76

Text Solution

Verified by Experts

The correct Answer is:
A
According to Raoult.s Law
`(P^@ - P_s)/(P_s) = (W_B xx M_A)/(M_B xx M_A)`…(i)
`(760-P_s)/P_s = (18xx18)/(180 xx 178.2)`…(ii)
On solving (ii) we get
`P_s = 752.4 torr`
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