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The normal boiling point of water is 373...

The normal boiling point of water is 373 k. vapour of waterr at temperature T is 19 mm hg. If enthalpy of vapoursed is 40.67 kJ/mol, them temperature Twould be
(use : log 2 = 0.3, R : 8.3` Jk^(-1)mol^(-1)`):

A

250 K

B

291.4K

C

230K

D

290 K

Text Solution

Verified by Experts

The correct Answer is:
B
Given `P_1= 19 mm Hg, P_2 = 760 mmHg`.
`DeltaH_("vap") = 40670 J//mol`
Applying Clausius - Clapeyron.s equation
`log""(P_2)/(P_1) = (DeltaH_(vap))/(2.303 xx8.3) ((373 - T_1)/(T_1 xx 373))`
on solving, we get `T_1 = 291. 4K`
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