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1.00 g of a non-electrolyte solute (mola...

1.00 g of a non-electrolyte solute (molar mass 250g `mol^(–1)`) was dissolved in 51.2 g of benzene. If the freezing point depression constant `K_(f)` of benzene is 5.12 K kg `mol^(–1)`, the freezing point of benzene will be lowered by:-

A

0.3 K

B

0.5 K

C

0.4 K

D

0.2

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaT = K_f m =(K_fxxwxx1000)/(mxxW) = 5.12 xx1/250 xx1000/51.2 = 0.4K`
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