Liquids A and B from an ideal solution and the former has stronger intermolecular forces. If `X_A and X'_A` are the mole fractions of A in the solution and vapour inequilibrium, then

Options

A. `(X'_A)/(X_A) = 1`
B. `(X'_A)/X_A gt 1`
C. `(X'_A)/(X_A)=1`
D. `X'_A + X_A =1`

Answer

C

Explanation

`x_A^.= p_A/p = (p_A^@ x_A)/p rArr x_A^./x_A = (p_A^@)/p lt 1`
(since the liquid A is less valatile,`p_A^@ lt P`)