At 760 torr pressure and `20^(@)C` tempreature , 1 L of water dissolves 0.04 gm of pure oxygen or 0.02 gm of pure nitrogen. Assuming that dry air is compound of 20% oxygen and 80% nitrogen (by volume), the masses (in g/L) of oxygen and nitrogen dissolved by 1 L of water at `20^(@)C` exposed to air at a total pressur of 706 torr are respectively :

Options

A. 0.008,0.016
B. 0.016,0.008
C. 0.16.0.08
D. 0.04,0.02

Answer

A

Explanation

Mass of oxygen `=20/100 xx 0.04 = 0.008 g //L`
Mass of nitrogen `= 80/100 xx 0.02 = 0.016 g//L`