A 0.001 molal solution of [Pt(NH(3))(4)C...

A 0.001 molal solution of `[Pt(NH_(3))_(4)CI_(4)]` in water had a freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, the correct formulation for the above molecule is

`[Pt (NH_3)_4Cl_3]Cl`

`[Pt (NH_3)_4Cl_2]Cl_2`

`[Pt (NH_3)_4 Cl]Cl_3`

`[Pt(NH_3)_4 Cl_4]`

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Verified by Experts

The correct Answer is:

`DeltaT_f = i.K_f.m, 0.0054 = ixx1.8 xx 0.001`
`i=3" so it is "[PT(NH_3)_4Cl_2]Cl_2`.

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