When 9.65 ampere current was passed for 1.0 hour into nitrobenzene in acidic medium, the amount of p-aminophenol produced is :

Options

A. 109.0 g
B. 98.1 g
C. 9.81 g
D. 10.9 g

Answer

C

Explanation

`9.65` ampere current was passed for 1.0 hour (3600 seconds)
Number of moles of electrons passed ` = (I (A) xx t (s))/(96500) = (9.65 A xx 3600 s)/(96500) = 0.36` moles
`C_(6) H_(5) NO_(2) + 4 e^(-) + 4H^(-) to p`- Aminophenol + `H_(2)O` 4 moles of electrons will reduce 1 mole of nitrobenzene to p-aminophenol .
0.36 moles of electron will reduce `(0.36)/(4) = 0.09` moles p - aminophenol molar mass = 109.14 g/mol
Mass of p - aminophenol obtained = 109.14 g /mol `xx 0.09` mol = 9.81 g