Standard electrode potential data is giv...

Standard electrode potential data is given below :
`Fe^(3+) (aq) + e ^(-) rarr Fe^(2+) (aq) , E^(o) = + 0.77 V `
`Al^(3+) (aq) + 3e^(-) rarr Al (s) , E^(o) = - 1.66 V `
`Br_(2) (aq) + 2e^(-) rarr 2Br^(-) (aq) , E^(o) = +1.08 V`
Based on the data given above, reducing power of `Fe^(2+)` Al and `Br^(-)` will increase in the order :

`Fe^(2+) lt Al lt Br^(-)`

`Br^(-) lt Fe^(2+) lt Al`

`Al lt Br^(-) lt Fe^(2+)`

`Al lt Fe^(2+) lt Br^(-)`

Text Solution

Verified by Experts

The correct Answer is:

Reducing characters decreases down the series . Hence the correct order is
`Al lt Fe^(2+) lt Br^(-)`

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Electrode potential data are given below: Fe^(3+)(aq)+e^(-)rarrFe^(2+)(aq):E^(@)=+0.77V Al^(3+)+3e^(-)rarrAl(s):E^(@)=-1.66V Br_(2)(aq)+2e^(-)rarr2Br^(-)(aq):E^(@)=+1.08V , Based on the data, the reducing power of Fe^(2+) Al and Br^(-) will increase in the order

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Based on the data given below, the correct order of reducing power is: Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V

Given : Fe^(2+)(aq)+2e^(-) rarr Fe(s), " "E^(c-)=-0.44V Al^(3)+3e^(-) rarr Al(s)," "E^(c-)=-1.66V Br^(2+)+2e^(-)rarr 2Br^(c-)(aq)" "E^(c-)=-1.08V The decreasing order of reducing power is ……………………………….. .

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