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If e(Fe^(2+) //Fe)^@ =- 0. 44 1V. And E(...

If `e_(Fe^(2+) //Fe)^@ =- 0. 44 1V`. And `E_(Fe^(3+)//Fe^(2+))^(o) = 0. 771 V`. The standard emf of the reaction ` Fe +2 Fe^(3+) rarr 3Fe^(2+)` will be .

A

`1.653` V

B

1.212 V

C

`0.111` V

D

`0.330` V

Text Solution

Verified by Experts

The correct Answer is:
B

`E_("cell")^(@) = E_("cathode")^(@) - E_("Anode")^(@)`
`= .771 - (-.441) = .771 + 441 = 1.212 V `
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