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Based on the cell notation for a sponta...

Based on the cell notation for a spontaneous reaction, at the anode:
`Ag(s)"|"AgCl(s)"|"Cl^(-)(aq)"||"Br^(-)(aq)"|"Br_2(l)"|"C(s)`

A

AgCl gets reduced

B

Ag gets oxidized

C

`Br^(-)` gets oxidized

D

`Br_(2)` gets reduced

Text Solution

Verified by Experts

The correct Answer is:
B
Ag becomes oxidized and `Br^(-)` becomes reduced .
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