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The E^(@) at 25^(@)C for the following r...

The `E^(@)` at `25^(@)`C for the following reaction is 0.22 V. Calculate the equilibrium constant at `25^(@)`C :
`H_(2)(g)+2AgCl(s)to2Ag(s)+2HCl(aq)`

A

`2.8 xx 10^(7)`

B

`5.2 xx 10^(8)`

C

`5.2 xx 10^(6)`

D

`5.2 xx 10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E^(@) = (0.0591)/(2) "log " K_(eq) log K_(eq) = (2 xx 0.22)/(0.0591)`
`implies 7.44 or K_(eq) = 2 . 8 xx 10^(7)`
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