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In the electrochemical reaction, 2Fe^(...

In the electrochemical reaction,
`2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+)`,
increasing the concentration of `Fe^(2+)` :

A

increases cell emf

B

increases the current flow

C

decreases the cell emf

D

alters the pH of the solution

Text Solution

Verified by Experts

The correct Answer is:
C

Nernst equation `E_(cell) = E_(cell)^(@) - (RT)/(nF) "ln" ([Fe^(2+)]^(2))/([Fe^(3+)]^(2)) [Zn^(2+)]` increasing `[Fe^(2-)]` will decreases the `E_(cell)`.
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