The molar conducatance of `Ba^(2+)` and `Cl^(-)` are `127` and `76 ohm^(-1) cm^(-1) mol^(-1)` respectively at infinite dilution. The equivalent conductance of `BaCl_(2)` at infinte dilution will be

Options

A. 203
B. 279
C. 101.5
D. 139.5

Answer

B

Explanation

Equivalent conductivity of `BaCl_(2)`
`Lambda_(m)^(oo) (BaCl_(2)) = Lambda_(m)^(oo) (Ba^(2+)) + 2 lambda_(m)^(oo) (Cl^(-)) = 127 + 2 xx 76 = 279 ohm^(-1) cm^(2) eq^(-1)`