If `X` is the specific resistance of the solution and `N` is the normality of the solution, the equivalent conductivity of the solution is given by

Options

A. `(1000 x)/(N)`
B. `(1000)/(Nx)`
C. `(1000 N)/(x)`
D. `(Nx)/(1000)`

Answer

B

Explanation

Specific resistance = x
`therefore` Specific conductance (or conductivity) = `k = (1)/(x)`
`therefore Lambda_(eq) = (k xx 1000)/(N) = (1000)/(x N)`