The correct order of equivalent conductance at infinite dilution of `LiCl, NaCl` and `KCl` is:

Options

A. `LiCl gt NaCl gt KCl`
B. `KCl gt NaCl gt LiCl`
C. `NaCl gt KCl gt LiCl`
D. `LiCl gt KCl gt NaCl`

Answer

B

Explanation

As we go down the group 1 (i.e. from `Li^+` to `K^+`) , the ionic radius increases , degree of solvation decreases and hence effective size decreases resulting in increase in ionic mobility . Hence equivalent conductance at infinite dilution increases in the same order .