The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will be

Options

A. `0.0616 cm^(-1)`
B. `0.66 cm^(-1)`
C. `6.60 cm^(-1)`
D. `660 cm^(-1)`

Answer

B

Explanation

Specific conductance of the solution (k) = `0.012 ohm^(-1) cm^(-1)` and resistance (R) = 55 ohm
Cell constant = Specific conductance `xx` Observed resistance = `0.012 xx 55 = 0.66 cm^(-1)`