A solution of sodium sulphate in qater is electrolysed using inert electrodes, The products at the cathode and anode are respectively.

Options

A. `H_(2) , O_(2)`
B. `O_(2) , H_(2)`
C. `O_(2) , Na`
D. `O_(2) , SO_(2)`

Answer

A

Explanation

Water is reduced at the cathode and oxidized at the anode instead of `Na^(+)` and `SO_(4)^(2-)`
Cathode : ` 2H_(2) O + 2e^(-) to H_(2) + 2 OH^(-)`
Anode : `H_(2) O to 2H^(+) + (1)/(2) O_(2) + 2 e^(-)`.