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If 0.5 amp current is passed through a...

If ` 0.5 ` amp current is passed through acidified silver nitrate solution for `10` minutes. The mass of silver deposited on cathode, is (eq. wt. of silver nitrate = `108`).

A

2.3523 g

B

3.3575 g

C

5.3578 g

D

6.3575 g

Text Solution

Verified by Experts

The correct Answer is:
B
Given current (i) = 0.5 amp ,
Time (t) = 100 minutes `xx` 60 = 6000 sec
Equivalent weight of silver (E) = 108
According to Faraday.s first law of electrolysis
`W = ("Eit")/(96500) = (108 xx 0.5 xx 6000)/(96500) = 3.3575 `g
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