The following facts are availabel `:`
`2A^(c-)+B_(2) rarr 2B^(-)+A_(2),`
`2C^(c-)+B_(2) rarr No reaction, `
`2D^(c-)+A_(2) rarr 2A^(c-)+D_(2)`
Which of the following statement is correct ?

Options

A. `E_(C^(-) |C_(2))^(@) gt E_(B^(-) | B_(2))^(@) gt E_(A^(-) |A_(2))^(@) gt E_(D^(-) |D_(2))^(@)`
B. `E_(C^(-) |C_(2))^(@) lt E_(B^(-) |B_(2))^(@) lt E_(A^(-) |A_(2))^(@) lt E_(D | D_(2))^(@)`
C. `E_(C^(-) | C_(2))^(@) lt E_(B^(-) | B_(2))^(@) gt E_(A^(-) | A_(2))^(@) gt E_(D^(-) | D_(2))^(@)`
D. `E_(C^(-) | C_(2))^(@) gt E_(B^(-) | B_(2))^(@) lt E_(A^(-) | A_(2))^(@) lt E_(D^(-) | D_(2))^(@)`

Answer

B

Explanation

Given examples are of non-metals . A non -metals having higher reduction potential replaces the other from its solution.
Thus , `E_(RP)^(@) D lt E_(RP)^(@) A lt E_(RP)^(@) B` or
Thus `E_(OP)^(@) D gt E_(OP)^(@) A gt E_(OP)^(@) B`
Thus only choice is (b) because `E_(QP)^(@) B lt E_(OP)^(@) C ` as B replaces C from solution .