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The equillibrium constant for thefollowi...

The equillibrium constant for thefollowing general reaction is `10^(30)`. Calculate `E^(@)` for the cell at 298 K.
`2X_(2)(s)+3Y^(2+)(aq)to2X_(2)^(3+)(aq)+3Y(s)`

A

`+0.105` V

B

`+0.2955` V

C

`0.0985 V`

D

`-0.2955 V`

Text Solution

Verified by Experts

The correct Answer is:
B
`K = 10^((6 xx FE^(@))/(2.303 RT))`
`log 10^(30) = (6 xx E^(@))/(0.0591) implies E^(@) = 0.2955 V `
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