The specific conductance of a saturated solution of silver bromide is `kScm^(-1)` . The limiting ionic conductivity of `Ag^+` and `Br^-` ions are x and y respectively. The solubility of silver4 vromide in `gL^(-1)` is : (molar mass of AgBr=188)

Options

A. `(k xx 1000)/(x - y)`
B. `(k)/(x + y) xx 188`
C. `(k xx 1000 xx 188)/(x + y)`
D. `(x + y)/(k) xx (1000)/(188)`

Answer

C

Explanation

`Lambda_(m) = (k)/(M) xx 1000 , (x + y) = (k)/(M) xx 1000`
`implies M = (1000 xx k)/((x + y))`
Solubility (in `gL^(-1)) = (k xx 1000 xx 188)/(x + y)`